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what will be the output of this program?
void main()
{
int a[]={5,10,15};
int i=0,num;
num=a[++i] + ++i +(++i);
printf("%d",num);
}
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Answer Posted / nandkishor
Ans: 19.
Explanation: First expression (++i) execute. Hence i=1;
Than a[++i]=a[2]=15.
And than ++i=3.
Hence evaluation will be 15+3+1=19.
Note that expression closed in braces have high precedence.
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