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2 ships are wardroom light house one side at 30 degree and other ship other side at 45 degree. If light house has 100 m, find distance of boat from light house.
and also find distance of each boat from light house
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Answer Posted / 100r@bh
distance between the two boats
Let AB be the light house and the two boats be at C and D
AB = 100 m
tan30° = BC/AB | BC = tan(30) * 100 = 57.7350
BC = 57.7350 m
tan45° = BD/AB | BD = tan(45) * 100 = 100
BD = 100 m
Therefore, the distance between the two boats is = BC+BD
= 57.7350+ 100
= 157.73 m
IF you find Both 2 Boat Distance from light house
AB2 + BC2 = AC2 || Square root(1002 + 57.73502 ) = 115.47 || AC = 115.47
AB2 + BD2 = AD2 || Square root(1002 + 1002 ) = 115.47 || AD = 141.42
| Is This Answer Correct ? | 4 Yes | 5 No |
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