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If the sum of n terms of two series of A.P are in the ratio
5n+4:9n+6 .find the ratio of their 13th terms
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Answer Posted / akshay b menon
(5n+4)/(9n+6)=((n/2){2x+(n-1)d})/((n/2){2x'+(n-1)d'})
=(2x+(n-1)d)/(2x'+(n-1)d')
=(x+{(n-1)/2}d)/(x'+{(n-1)/2}d')
implies,
m=(n-1)/2
2m-1=n
since m=13,n=25
substituting value of n in given ratio
(5*25+4)/(9*25+6)=129/231
| Is This Answer Correct ? | 45 Yes | 47 No |
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