why commutator are not used in rectification purpose in power
electronics?
- 1 Answers
- 2935 Views
- I also Faced
- E-Mail Answers
Answer Posted / guna
Commutator function is to deliver the dc supply at the
output terminals, it only happens when there is a
rotating part on the equipment cause it reverses the emf
when there is an alternate south and north pole crosses
at the mid point of plane. The collection of current only
possible when there is a carbon or copper brushes
attached on the surface. So We cant see the whole setup
in power electronic devices, And more over that, the main
objective of power electronic devices is to operate at
higher current and voltage levels within compact sizes
(tiny size), for reliability. Due to rotational parts
losses also increases & wiring cost & insulation
required. Commutator can't terminate the ripples or
disturbances in the output supply but power electronic
equipment's can do. So power electronic devices more
sophisticated than commutator.
| Is This Answer Correct ? | 9 Yes | 0 No |
Post New Answer View All Answers
How to arrange a hous hold earthing system to keep minimum earth resistance( below 7ohms).
describe the Tranformer testing procedure
Is it acceptable of installing an earth pit in planters area where bare copper cable, earth rod and connection are susceptible to corrosion due to water?
whit is 33kv power 300*300 cable full current with formula
how calculate the electrical load for industry and office
How we calculate DC inducation moter Amp? Sir pls give me formula......
what is positive , negative & zero equivalent system resistance
What do you mean by distribution transformers?
difference between the applicability of nortons and thevenin theorem
Difference between control junction box (cjb) and power junction box(pjb)?
what is meant by re-rolling motor? how it differs from standard motor?
Control cables in S's will carry 1000v which is AC R DC? Pls answer me
An 8 pole, 50 Hz, 3-phase IM is loaded to a poing where pull out torque will occur. The rotor resistance per phase is 0.3 ohm and motor stalls at 650 rpm. The slip when motor stalls is A 1 B 0 C 13.33% D 10.33%
What willbe change in programming when we use 5/3 solenoid inplace of 5/2 in operating of a cylinder?
Give the topology of current amplifier with current shunt feedback?
