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f(char *p)
{
p=(char *)malloc(sizeof(6));
strcpy(p,"HELLO");
}
main()
{
char *p="BYE";
f(p)
printf("%s",p);
}
what is the output?
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Answer Posted / deepa
the outpu is hello coz the pointer is pointing to a
location where the string "bye" is written in the next
program yu are using the same pointer to point to some
other string so it gets overwritten
| Is This Answer Correct ? | 2 Yes | 5 No |
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