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I have a orifice installed in plant which is design for
0~100 inH2O for 0~80MMSCFD, now due to process change the
maximum flow is change to 120 MMSCFD so for this new
process value what will be the DP across orifice.
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Answer Posted / carl_ellis
100 in H2O = 80 MMSCFD
x = 120 MMSCFD
Maximum flow rate is the square root of the normalized
percentage of the maximum DP (at the maximum flow rate)
The maximum flow rate increases 150% of the original max
flow rate:
120/80 = 1.50, so 120 MMSCFD is 150% of 80 MMSCFD, or a 50%
increase in maximum flow rate
To calculate the corresponding DP at a max flow rate 150%
higher than the original, where X = DP
sq rt of X = 1.50 (square root of normalized percentage of DP)
X = 1.50^2 = 2.25
2.25 = 225% (work in normalized percentage)
225% of 100 inH2O = 225 in H2O at a max flow rate of 120 MMSCFD
Carl Ellis
Measure First
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