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What will be the output of the following program :
void main()
{
int a,b,c;
scanf("%1d %2d %3d",&a,&b,&c);
printf("Sum=%d",a+b+c);
}
[NOTE : THE USER INPUT IS :123456 44 544]
(a)Sum=480 (b)Sum=594 (c)Sum=589 (d)None of these
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Answer Posted / ravinder
The answer is 480
Here it takes the first number as string
for %1d it takes first number 1 from 123456
for %2d it takes next two numbers 23 from 123456
for %3d it takes the remaining 456 from 123456
so sum is 1
23
456
----
480
| Is This Answer Correct ? | 13 Yes | 3 No |
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