in the first case equals method compares the sequence of characters pointed

If I will write
String s=new String("XYZ");
String s1=new String("XYZ");
if(s.equals(s1)){
sop("True");
}
else{
sop("False");
}
This program will give me "True".
But When I am creating my own class suppose
class Employee{
public Employee(String name);
}
Employee e= new Employee("XYZ");
Employee e1 = neew Employee("XYZ");
if(e.equals(e1)){
sop("True");
}
else{
sop("False");
}
Then it will give the output as "False".
Can I know what is happening internally?

Question Posted / sindhu

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Answer Posted / sindhu

in the first case equals method compares the sequence of characters pointed by s and s1. as both are same it returns true. in the second case it is comparing the references i.e addresses of objects e and e1. as both are not same, it returns false.

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