f returns (n * 2^(l-r)) n<<l => n * 2^l (n<<l)>>r

what is the purpose of the code, and is there any problem
with the code?

int f( int n, int l, int r )
{ return (n << l) >> r; }

Question Posted / senthil

Answer Posted / senthil

f returns (n * 2^(l-r))

n<<l => n * 2^l
(n<<l)>>r => (n * 2^l)/(2^r)=>(n * 2^(l-r))

Is This Answer Correct ?

1 Yes

0 No

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