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main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
}
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Answer Posted / c.p.senthil
Ans = 8
Explanation:
after brackets post increment has higher precedence,
hence expression can be viewed as
(*ptr)++ + *ptr++
printf("%d",(*ptr)+++*ptr++); can be expanded in 3 steps as
1. printf("%d",(*ptr)+*ptr); => displays 4+4
2. ptr++; => increments the pointer to next location
3. (*ptr)++; => increments the value in that location
This program can be better understood, with the below modification
main()
{
int *ptr=(int*)malloc(sizeof(int)*2);
*ptr=4; // current location value = 4
*(ptr+1) = 10; // next location value = 10
printf("%d\n",(*ptr)+++*ptr++); // display 8 (4+4)
printf("%d\n",*(ptr-1)); // current location value = 4
printf("%d\n",*ptr); // next location value = 10+1 = 11
}
| Is This Answer Correct ? | 3 Yes | 3 No |
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