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what is the purpose of the code, and is there any problem
with it.
unsigned int v[10];
unsigned int i = 0;
while (i < 10)
v[i] = i++;
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Answer Posted / arka bandyopadhyay
Basically it's a tricky question and the values of v[i] cannot be predicted as there is "i++" which means 'use than change'
that is error associated with the program so using ++i will give us the correct result.
| Is This Answer Correct ? | 4 Yes | 3 No |
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