Answer Posted / shinu

For 1 m3 of concrete (1:2:4)
Required volume of concrete=1.00
Add 35% extra for additional voids in concrete ie 1.35
Therefore Total qty=1.35Cum
Total Mix=1+2+4=7

Therefore Quantity of cement =1.35/7= 0.193Cum
Qty of Cement in Kgs = (0.193*1440)=277.92 Kgs
In Bags, 277.92kg/50kg=5.56 bags
otherwise
1cum Cement=1440Kgs ie 28.8 bags
In Bags 28.8*.193=5.56

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