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how much brick,cement,and sand required in 1cum
brickwork(1:4)
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Answer Posted / suneel.p
brick size 0.23*0.1*0.1(1:4)
valum of brisk : 0.0023cum
say 12mm thick mortar or brick layar((0.23+.0006)*(0.1+.0006)*(0.1+.0006)
so volume of brick: 0.00265
no.of bricks in 1cum=1/0.00265=378 no.s
volum of brik for 1cum=378*0.0023=0.869cum
volum of mortar 1-0.869=0.131
add30% for dry mortar of =0.30cum
add 10% for wastages =0.10cum
total volum of mortar =0.40 cum
for c:m =1+4=5
qantay of cemant 1/5*0.4=0.08 cum
1cum of cemant =(1440/50)=28.8bags
=.08*28.8=2.304bags
sand =4/5=0.8*0.4=0.32cum
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