Answer Posted / kiran

/*
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* and open the template in the editor.
*/
package removespacesfrommatrix;

/**
*
* @author Sunshine
*/
public class RemoveSpacesFromMatrix {

void print(char[][] matrix) {
char temp;
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 4; j++) {
if (matrix[i][j] != ' ') {
System.out.println(matrix[i][j]);
} else {
temp = matrix[i][j + 1];
matrix[i][j] = temp;
matrix[i][j + 1] = ' ';
System.out.println(matrix[i][j]);
}
}
}
}

/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
char[][] matrix;
matrix = new char[][]{{'a', 'b', ' ', 'c'}, {' ', 'd', ' ', 'f'}, {' ', ' ', 'x', 'y'}, {'m', 'n', 'o', 'p'}};
RemoveSpacesFromMatrix r = new RemoveSpacesFromMatrix();
r.print(matrix);
}
}

U hv to enter a range from a and b and search hw many no. of times a pattern n. occurs between the range a and b. Eg :i/p:enter range :0 100 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 0 to 100:1 Eg :i/p:enter range :100 1000 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 100 to 1000: (in this 13,113,131,132,133…139,213,313,…913 all these will be counted)

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output for printf("printf");

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Code for Easily Using Hash Table?

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Performance Algorithm A performs 10n2 basic operations and algorithm B performs 300 lg n basic operations. For what value of n does algorithm B start to show its better performance?

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write a program that creates a sequenced array of numbers starting with 1 and alternately add 1 and then 2 to create the text number in the series , as shown below. 1,33,4,6,7,9,............147,148,150 Then , using a binary search , searches the array 100 times using randomly generated targets in the range of 1 to 150

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