write the function. if all the character in string B appear in
string A, return true, otherwise return false.
Answer Posted / sravanthi
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
int main()
{
char *a;
a=(char*)malloc(20*sizeof(char));
char *b;
b=(char*)malloc(20*sizeof(char));
int i,j,flag,count,n;
i=j=count=flag=0;
printf("enter the string 1");
gets(a);
printf("enter the string 2");
gets(b);
n=strlen(b);
while(b[j]!='\0')
{
i=0;
flag=0;
while(a[i]!='\0')
{
if(a[i]==b[j])
{
flag=1;
break;
}
else
{
i++;
}
}
if(flag==1)
{
count=count+1;
}
j++;
}
if(count==n)
{
printf("true");
}
else
{
printf("false");
}
getch();
}
Is This Answer Correct ? | 2 Yes | 0 No |
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