Answer Posted / mayank

/*write a program to accept any number up to five digits and
print that in words(without using array). for example- 1265=
one two six five*/
#include<stdio.h>
#include<stdlib.h>
main()
{
int x,mod, rev=0;
printf("enter number(up to five digits)");
scanf("%d", &x);
if(x>99999)
{
printf("invalid number");
exit(0);
}
while(x>0)
{
mod=x%10;
rev=rev*10+mod;
x=x/10;
}
while(rev>0)
{
mod=rev%10;
switch(mod)
{
case 1:
printf("one ");
break;
case 2:
printf("two ");
break;
case 3:
printf("three ");
break;
case 4:
printf("four ");
break;
case 5:
printf("five ");
break;
case 6:
printf("six " );
break;
case 7:
printf("seven ");
break;
case 8:
printf("eight ");
break;
case 9:
printf("nine ");
break;
case 0:
printf("zero ");
break;
}
rev=rev/10;
}
printf("\n");
}

A banker has a seif with a cipher. Not to forget the cipher, he wants to write it coded as following: each digit to be replaced with the difference of 9 with the current digit. The banker chose a cipher. Decipher it knowing the cipher starts with a digit different than 9. I need to write a program that takes the cipher from the keyboard and prints the new cipher. I thought of the following: Take the input from the keyboard and put it into a string or an array. Go through the object with a for and for each digit other than the first, substract it from 9 and add it to another variable. Print the new variable. Theoretically I thought of it but I don't know much C. Could you give me any kind of hint, whether I am on the right track or not?

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