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There are 4 segment registers in 8086 microprocessor.Each
of the segment register is of 64kb.Then (4*64)=256kb.The
total memory in 8086 is 1mb.What about the rest of the
memory space?
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Answer Posted / reza r
As far as I know, the external address bus in 8086 is 20
Bits, thus the maximum addressable memory blocks are 1Mega
(1048576) in 8086, memory is byte addressable, so the
maximum addressable memory is 1Mega Bytes.
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