Answer Posted / silky

#include<stdio.h>
#include<string.h>
#include<iostream>
using namespace std;

int main()
{
char a[100],s[100];
gets(a);
int i,c[27],j;

for(int i=0;i <=26;i++)
c[i]=0;

for(i=0;i<strlen(a);i++)
{
if(a[i]>='a' && a[i]<='z')
{
c[ a[i] - 'a' ]++;
}
}

for(j=0;j <=26;j++)
{
if(c[j]>0)
{
printf("%c occurs %d times\n ",'a'+j,c[j]);
}
}

}

A banker has a seif with a cipher. Not to forget the cipher, he wants to write it coded as following: each digit to be replaced with the difference of 9 with the current digit. The banker chose a cipher. Decipher it knowing the cipher starts with a digit different than 9. I need to write a program that takes the cipher from the keyboard and prints the new cipher. I thought of the following: Take the input from the keyboard and put it into a string or an array. Go through the object with a for and for each digit other than the first, substract it from 9 and add it to another variable. Print the new variable. Theoretically I thought of it but I don't know much C. Could you give me any kind of hint, whether I am on the right track or not?

1779

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