Answer Posted / mrityunjay yadav

#include<stdio.h>
struct students
{
int Roll_no;
char name[50];
char deptt[20];
char course[30];
int year_of_passing;
};
void main()
{
struct students s[500];
int n,i,year,rollno,ccy,found=0;

clrscr();

printf("\nEnter number of students : ");
scanf("%d",&n);
printf("\nEnter the course completion period(in years) : ");
scanf("%d",&ccy);

printf("\nEnter student details : \n");
for(i=0;i<n;i++)
{
printf("\n\nEnter details for student : %d",i+1);
printf("\nRoll No : ");
scanf("%d",&s[i].Roll_no);
printf("\nName : ");
scanf("%s",s[i].name);
printf("\nDepat. : ");
scanf("%s",s[i].deptt);
printf("\nCourse : ");
scanf("%s",s[i].course);
printf("\nYear of Passing : ");
scanf("%d",&s[i].year_of_passing);
}
printf("\nQuestion 1 -> Enter the year of joining : ");
scanf("%d",&year);
printf("\nName of the Students\n------------------------------…
for(i=0;i<n;i++)
{
if(s[i].year_of_passing==(ccy+year))
{
printf("\n%s",s[i].name);
found=1;
}
}
if(found==1);
else printf("\nNo record Found\n");
found=0;
printf("\nQuestion 2 -> Enter the roll no : ");
scanf("%d",&rollno);

if(s[i].Roll_no==rollno)
{
found=1;
printf("\nName : %s\nDept. : %s\nCourse :
%s\n",s[i].name,s[i].deptt,s[i].course);
}
if(found==1);
else printf("\nNo record Found\n");

getchar();
}

a program that can input number of records and can view it again the record

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