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Can u any 1 please explain the below question and answer?
Given the following code, which statement is true about the
minimum number of test cases required for full statement and
branch coverage?
Read p
Read q
IF p q > 100 THEN
Print "Large"
ENDIF
IF p > 50 THEN
Print "p Large"
ENDIF
a) 1 test for statement coverage, 3 for branch coverage
b) 1 test for statement coverage, 2 for branch coverage
c) 1 test for statement coverage, 1 for branch coverage
d) 2 tests for statement coverage, 2 for branch coverage
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Answer Posted / suyash
The answer is B.
Statement Coverage (SC):
To calculate Statement Coverage, find out the shortest
number of paths following
which all the nodes will be covered. Here by traversing
through path 1A-2C-3D-E-4G-5H all
the nodes are covered. So by traveling through only one path
all the nodes 12345 are covered,
so the Statement coverage in this case is 1.
Branch Coverage (BC):
To calculate Branch Coverage, find out the minimum number of
paths which will
ensure covering of all the edges. In this case there is no
single path which will ensure coverage
of all the edges at one go. By following paths
1A-2C-3D-E-4G-5H, maximum numbers of
edges (A, C, D, E, G and H) are covered but edges B and F
are left. To covers these edges we can follow 1A-2B-E-4F. By
the combining the above two paths we can ensure of traveling
through all the paths. Hence Branch Coverage is 2. The aim
is to cover all possible true/false
decisions.
| Is This Answer Correct ? | 10 Yes | 2 No |
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