Answer Posted / jaroosh

"char *(*(*a[])())();"
is a string, but
char *(*(*a[])())();
is NOT.
It is simply a function pointer declaration, which says :
"declare an array named 'a', of pointers to functions that
take no arguments and return a pointer to a function that
takes no arguments and returns a pointer to char"...thew,
reading function pointers is actually kinda complicated.

NOTE: char *(*(*a[])())(); is an erroneous declaration, for
it to be proper, you have to specify array size, eg:
char *(*(*a[5])())(); will work.

any function have arguments one or more OR not . it is compulsary a) any function compulsary have one or more arguments b) any function did not have arguments. It is not compulsary c) it is optional it is not compulsary d) none of the above

645

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What is ctrl c called?

598

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What would happen to X in this expression: X += 15; (assuming the value of X is 5)

1306

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601

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how can use subset in c program and give more example

1502

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667

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Write a program that accept anumber in words

1252

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What are pragmas and what are they good for?

577

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630

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What will the code below print when it is executed?   int x = 3, y = 4;         if (x = 4)                 y = 5;         else                 y = 2;         printf ("x=%d, y=%d ",x,y);

1358

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What is #include stdio h and #include conio h?

603

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1622

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641

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For what purpose null pointer used?

609

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