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void main()
{
int a=1;
printf("%d %d %d",a,++a,a++);
}
the output is supposed to be 1 2 2....but it is 3 3 1
this is due to calling conventions of C. if anyone can
explain me how it happens?
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Answer Posted / pranjal kumbang
Output:3 3 1 This
is because,C's calling convention is from right to left.That
is ,firstly 1 is passed through the expression a++ and then
a is incremented to 2.Then result of ++a is passed.That is,a
is incremented to 3 and then passed.Finally,latest value of
a,i.e. 3,is passed.Thus in right to left order,1 ,3, 3 get
passed.Once printf() collects them,it prints them in the
order in which we have asked it to get them printed(and not
the order in which they were passes).thus 3 3 1 gets
printed.
| Is This Answer Correct ? | 8 Yes | 2 No |
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