to find the program of matrix multiplication using arrays
Answer Posted / mani prakesh
#include<stdio.h>
#include<conio.h>
main()
{
int i,j,r1,c1,r2,c2,m1[2][2],m2[2][2],k,mult[2][2];
printf("Enter rows and columns of first matrix \n");
printf("Again row wise\n");
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
scanf("%d",&m1[i][j]);
}
printf("You have entered the first matrix as follows:\n");
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
printf("%d\t",m1[i][j]);
printf("\n");
}
printf("Enter rows and columns of Second matrix \n");
printf("Again row wise\n");
for(i=0;i<r2;i++)
{
for(j=0;j<c2;j++)
scanf("%d",&m2[i][j]);
}
printf("You have entered the second matrix as
follows:\n");
for(i=0;i<r2;i++)
{
for(j=0;j<c2;j++)
printf("%d\t",m2[i][j]);
printf("\n");
}
// Matrix Multiplication
if(r2==c1)
{
printf("Now we multiply both the above matrix \n");
printf("The result of the multiplication is as
follows:\n");
/*a11xA11+a12xA21+a13xA31 a11xA12+a12xA22+a13xA32
a11xA13+a12xA23+a13xA33*/
for(i=0;i<r1;i++)
{
for(j=0;j<c2;j++)
{
mult[i][j]=0;
for(k=0;k<r1;k++)
{
mult[i][j]+=m1[i][k]*m2[k][j];
/*mult[0][0]=m1[0][0]*m2[0][0]+m1[0][1]*m2[1][0]+m1[0][2]*m2[2][0];*/
}
printf("%d\t",mult[i][j]);
}
printf("\n");
}
}
else
{
printf("Matrix multiplication cannot be done");
}
getch();
}
Is This Answer Correct ? | 4 Yes | 1 No |
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