Answer Posted / devyani

Below is a simple program as an example:
IF A = 354
THEN IF B > C
THEN A = B
ELSEA= C
ENDIF
ENDIF
Print A
The control flow generated from the program would look like Figure 3.2.
The control flow shows seven nodes (shapes) and eight edges (lines), thus using the formal formula the cyclomatic complexity is 8-7 + 2 = 3. In this case there is no graph called or subroutine. Alternatively one may calculate the cyclomatic complexity using the decision points rule. Since there are two decision points, the cyclomatic complexity is 2 + 1 = 3.

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