Which is the only operator in C++ which can be overloaded
but NOT inherited?
Answer Posted / sharathnasa
#include <iostream>
#include <iomanip>
using namespace std;
class A {
public:
int _i;
A(int i) : _i(i) { }
virtual A &operator=(A const &other) {
if (this!=&other) {
_i = other._i;
}
return *this;
}
virtual A operator+(A const &rvalue) {
return A(_i + rvalue._i);
}
virtual void print() {
cout << "A(_i=" << _i << ")";
}
};
class B : public A {
public:
int _j;
B(int i, int j) : A(i), _j(j) { }
virtual void print() {
cout << "B(_i=" << _i << ", _j=" << _j <<")";
}
};
int main() {
A a1(5), a2(3);
a1.print();
cout << " + ";
a2.print();
cout << " = ";
A a3 = a1 + a2;
a3.print();
cout << endl;
B b1(5,3), b2(3,5);
b1.print();
cout << " + ";
b2.print();
cout << " = ";
// this works, although (b1+b2) returns an A since it uses
A's operator+
(b1+b2).print();
// this does not work: no conversion from A to B, i.e.
operator= not inherited
// B b3 = b1 + b2;
// b3.print();
cout << endl;
return 0;
}
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