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&#8206;#define good bad
main()
{
int good=1;
int bad=0;
printf ("good is:%d",good);
}

Answer Posted / suresh kumar beniwal

multiple declaration of bad
so error occur
write program is

#define good bad
main()
{
int good=1;
bad=0;
printf ("good is:%d",good);
}

output :
good is : 0

Is This Answer Correct ?    3 Yes 0 No



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