Answer Posted / leon

#include<stdio.h>
#include<conio.h>
int main()
{
long int n1,n2,r=0,sum[50];
int n,i=0;
clrscr();
printf("\n\n Enter First Binary Number: ");
scanf("%ld",&n1);
printf("\n\n Enter Second Binary Number: ");
scanf("%ld",&n2);

while (n1!=0 || n2!=0)
{
sum[i++]=(n1%10+n2%10+r)%2;
r=(n1%10+n2%10+r)/2;
n1=n1/10;
n2=n2/10;
}
if(r!=0)
sum[i++]=r;

printf("\n\n Sum of two binary numbers: ");

for(i=i-1;i>=0;i--)
printf("%d",sum[i]);

getch();
return 0;
}

int i[2], j; int *pi;i[0] = 1; i[1] = 5; pi = i; j = *pi + 1 + *(pi + 1)Value of j after execution of the above statements will be a) 7 b) 6 c) 4 d) pointer

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write a c program to find the sum of five entered numbers using an array named number

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