Answer Posted / david e. west
I wonder if the nujmber 4100 was picked because it is only 4
more than the "round number" 4096, which is the typical page
size on most 32-bit MMU paging architectures and whose hex
value is 0x1000. Then just add 4 for 0x1004. (Or maybe I'm
over thinking it.)
| Is This Answer Correct ? | 0 Yes | 2 No |
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