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Answer Posted / ramesh
#include<iostream.h>
#include<conio.h>
void main()
{
int sum=0,n,m;
clrscr();
cin>>n;
m=n;
while(n>0)
{
m=n%10;
sum=sum+(m*m*m);
n=n/10;
}
if(m==sum)
{
cout<<"the given number is amstrong";
}
else
{
cout<<"the given number is not amstrong";
}
getch();
}
| Is This Answer Correct ? | 4 Yes | 3 No |
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