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There are two candles of equal lengths and of different
thickness. The thicker one lasts of six hours. The thinner
2 hours less than the thicker one. Ramesh lights the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. How
long ago did Ramesh light the two candles .
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Answer Posted / sunil
let us assume the total units is lcm(6, 4)= 12 units;
candle 1 lasts 6 hours => in 1 hour the candle 1 lasts 2 units,
caldle 2 lasts 6-2 = 4 hours => in 1 hour the candle 2 lasts
3 units.
there fore remaining units for candle 1 after t hours is 12-2t
remaining units for candle 2 after t hours is 12-3t
there fore (12 - 2t) = 2(12 - 3t) [from the question]
=> 12 - 2t = 24 - 6t
=> 6t - 2t = 24 - 12
=> 4t = 12
=> t = 3 hours.
3 hours ago ramesh light the two candles.
| Is This Answer Correct ? | 5 Yes | 2 No |
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