Answer Posted / professor pandit

Java does not support multiple inheritance of classes.
Answer as to its reasons on why it does not support MI runs
much deeper than what generally seems to be written above.

Java like all OO languages aims to regulate and stream-line
the way in which average developer thinks. It is true that
in real world (from software designer perspective), an
entity, an object does exhibit functions from seemingly
different sets (aka classes).

It is true that implementing multiple inheritance is
difficult at compiler level and complexity is hardly ever
clearly explained in any example. Every single example of
MI that demonstrates its complexity seems contrived and are
generally name-collisions. Assuming that I did seriously
want to inherit class C from both A and B, why on earth
would I give same names to two distinct functions
originating from class A and class B? One could be foo()
and other could be foofoo(); (I hope you get the drift).

C++ designers bent-over-their-back and solved the problem
of MI and even the diamond problem.

Although, Diamond problem is successfully handled by C++,
any sane designer team could have a coding standards that
favour avoidance Diamond inheritance until the die-hard
developer convinces upper crust of its essentials.

Ironically, the major part of Java's decision on "why" of
avoiding MI lies in C++ implementation of it.

While I am grossly simplifying here, Crux of C++ solution
of implementing MI under the hood hinges upon properly
managing the v-table at run-time and unambigious usage of
redundant methods ( in case of diamond) are handled.

In case of Java, design goal was operability across
multiple platforms and industrial strength stability.

Both of these goals can be seriously compromised if MI (and
C++ solution of v-table) were implemented.

Therefore, Java designers choose to let go of a smaller
nice-to-have feature (MI for classes) in favour of Multiple
Platform (essential design goal)

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