posted by surbhi just now
main()
{
float a = 5.375;
char *p;
int i;
p=(char*)&a;
for(i=0;i<=3;i++)
printf("%02x",(unsigned char) p[i]);
}
how is the output of this program is ::
0000ac40
please let me know y this output has come
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Answer Posted / govind verma
i think mr sandeep this value stored in this manner
0100 0000 1010 1100 0000 0000 0000 0000 which is 40ac0000
float takn 4 byte in memory in program p=(char*)&a casting this to char type nw p(it char ponter its point to i byte value) point to lower byte of the a(5.375) which is 0000 0000
p[0]-> contain the fist lower byte data 00(bcoz print bye the hexa formate specifier withe 2 width)
p[1]->contain 00
p[2]-> contain ac
p[3]->contain 40
then output becom ...0000ac40
| Is This Answer Correct ? | 7 Yes | 0 No |
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