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f(char *p)
{
p=(char *)malloc(sizeof(6));
strcpy(p,"HELLO");
}
main()
{
char *p="BYE";
f(p)
printf("%s",p);
}
what is the output?
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Answer Posted / anu
the output wll be hello , since the argument is overwritten
with new memory in the function.
so in main, when it comes to printf, p points to the
allocatd memory, which contains hello
| Is This Answer Correct ? | 0 Yes | 3 No |
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