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A starts from a place at 11.00 am and travels at a speed of
4 kmph , B starts at 1.00 pm and travels with speeds of 1
kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the
next hr and so on. At wht time will B catch up with A ?
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Answer Posted / satish raj
A covers 8km till 01.00:pm and B starts at 01.00pm.hence at this point distance among them is 8km.
hence after 1hour at 02.00pm distance among them will be
11 km(i.e with a relative speed of 4-1=3km/h A will cover increase 3km gap).
At 03.00 pm,distance among them will be 13km(i.e. with a relative speed 4-2=2km/h and hence increase 2km gap)
hence,At 04.00- distance among them will be 14km.
at 05.00-distance among them will be 14km.
now 05:00pm-06:00pm slot relative speed will be countable and going with it- we will get 13hr-11hr-8hr-4hr and this 4 gap of will be completed in 4/5 hour=48min(because at that slot relative speed of B will be 5km/h).
ans:-09.48:pm
| Is This Answer Correct ? | 2 Yes | 1 No |
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