Given an array of characters which form a sentence of
words, give an efficient algorithm to reverse the order of
the words (not characters) in it.
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Answer Posted / raghuram.a
/*complexity-2n..check d prog. */
#include<iostream.h>
#include<string.h>
#include<stdio.h>
void rev_word(char str[20],int m,int n)
{
int i,l,k;
k=n-m+1;
if(k%2==0)
l=(k/2-1);
else
l=k/2;
k=n;
for(i=m;i<=m+l;i++)
{ count++;
char t=str[i];
str[i]=str[k];
str[k]=t;
k--;
}
}
int main()
{
char str[100];
int i,j=0;
cout<<"\n\nenter string:";
gets(str);
rev_word(str,0,strlen(str)-1);
for(i=0;i<=strlen(str);i++)
{ count++;
if(str[i]==' '||str[i]=='\0')
{
rev_word(str,j,i-1);
j=i;
while(str[j]==' ')
j++;
i=j;
}
}
cout<<"\n\nsentence with order of words reversed is:";
cout<<str;
return 0;
}
| Is This Answer Correct ? | 0 Yes | 6 No |
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