write the function. if all the character in string B appear in
string A, return true, otherwise return false.
Answer Posted / raghuram.a
#include<iostream.h>
#include<string.h>
int h(char letter)
{
return(letter-97);
}
int main()
{
char str1[100],str2[100];
int i=0,count[26];
for(i=0;i<26;i++)
count[i]=0;
clrscr();
cout<<"\n\nenter 1st string:";
cin>>str1;
cout<<"\n\nenter 2nd string:";
cin>>str2;
for(i=0;i<strlen(str1);i++)
{
count[h(str1[i])]++;
}
for(i=0;i<strlen(str2);i++)
{
count[h(str2[i])]--;
} int flag=0;
for(i=0;i<26;i++)
{if(count[i]!=0)
{cout<<"\n\nnot anagrams";
flag=1;
break;
}
}
if(flag==0)
cout<<"\n\nanagrams";
return 0;
}
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