write the function. if all the character in string B appear in
string A, return true, otherwise return false.
Answer Posted / raghuram
#include<iostream.h>
#include<stdio.h>
#include<string.h>
int main()
{
char str1[100],str2[100];
int flag1=0,flag=0;
cout<<"\n\nenter 1st string:";
cin>>str1;
cout<<"\n\nenter 2nd string:";
cin>>str2;
int i=0,j=0;
for(i=0;i<strlen(str1);i++)
{ flag=0;
for(j=0;j<strlen(str2);j++)
{
if(str1[i]==str2[j])
{flag=1;
str2[j]=' ';
break;
}
}
if(flag==0)
{
flag1=1;
cout<<"\n\nnot anagrams";
break;
}
}
if(flag1!=1)
cout<<"\nanagrams";
return 0;
}
| Is This Answer Correct ? | 1 Yes | 0 No |
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