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three circles with same radius r are drawn with centres as
three vertices of a triangle.what is the sum of areas of the
intersections of these circles with the triangle
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Answer Posted / y.lakshmi gayathri
ans:(1/2)*pie*r^2
as the sum of internal angles of triangle is 180 degrees
it cuts the all the 3 circles with the sum of 180 degree so
half of the area of circle
| Is This Answer Correct ? | 59 Yes | 8 No |
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