Answer Posted / sabab ali khan
becouse the value of given index are multiplied by size of
datatype of array and then add in the base Address to find
address of that block which you want to access
ex.
int arr[5];
if the base address of array is 1001 then last block
address will be 1009
and if we give arr[2] then compiler calculate address like
this..
1001 + sizeof(int)* 2 = 1005
where base address = 1001
and 2 is the given index.
so the calculated address is 1005 and third block will be
access.
| Is This Answer Correct ? | 7 Yes | 5 No |
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