Answer Posted / atul shukla

in list 12 all can be even or all can be odd so it require
3 array of same size

#include<stdio.h>
void main()
{
int a[12],even[12],odd[12],i,c=0,d=0;
printf("enter 12 numbers");
for(i=0;i<12;i++)
scanf("%d",&a[i]);
for(i=0;i<12;i++)
(n[i]%2==0)?even[c++]=a[i]:odd[d++]=a[i];
printf("seprate list of odd entries");
for(i=0;i<=d;i++)
printf("%d",odd[i]);
printf("seprate list of even entries");
for(i=0;i<=d;i++)
printf("%d",even[i]);
}

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