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if there are 30 cans out of them one is poisoned if a
person tastes very little he will die within 14 hours so if
there are mice to test and 24 hours, how many mices are
required to find the poisoned can?
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Answer Posted / abhishek jain
5 mice are needed.
let them be A,B,C,D,E.
let the drinking pattern be as follows:
A to E drink alone frm bottle 1-5.
all the possible combination of two i.e 5C2 number of bottles are drunk by A&B, B&C, A&E...and all possible 5C2 combinations.
all the possible 5C3 bottle nos. are drank by all posible three numbered groups i.e ABC, ABD and so on.
all possible 4 mice combinations drink from 5C4=5 bottles.
so total no. of bottles drank from = 5+ 5C2+ 5C3+ 5C4= 5+10+10+5=30
depending on the group of mice died, we can find the bottle no. which is poisned.
we cannot use one mouse split time technique because mouse dies within 14 hrs NOT after exactly 14 hrs. so ambiguity may arise as at an instant of time, more than on bottle can be held responsible for death.
| Is This Answer Correct ? | 33 Yes | 7 No |
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