Answer Posted / vishnutom

For 1 m3 of concrete (1:2:4)
for Required volume of concrete 1.00
Add extra for additional voids in concrete ( 25% to 35%)=Say
35%=35/100=0.35.

Total qty=1+0.35=1.35 Cum
Mix total (1+2+4)=7

Therefore Quantity of cement = (1.35/7)=0.19 Cum

Qty of Cement in Kgs = (0.19*1440)=273.6Kgs
(1cum=1440Kgs)
Qty of Cement in bags= 273.6/50=5.4 bags=Say 6 bags
(50kgs=1 bag)
Qty of sand in bags = ( 0.19*2)=0.39Cum
Qty of Aggregate = ( 0.19*4)=0.77Cum

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