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main()
{
int i = -3,j=2,k=0,m;
m= ++i || ++j && ++k;
printf("%d%d%d",i,j,k,m);
}
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Answer Posted / harend
results :
i=-2
j=2
k=0
m=1
First, the '&&' part is to be considered over '||'.
AS follow: m = ++i||++j&&++k (is given)
what ever be the result of (++j&&++k),the value of m =1
,since the new value i= -2 (i.e a non zero value so taken as
true or 1)
so,
1||(++j&&++k) will always be true, that is 1 . compiler
ignores ++j ,++k and only consider ++i.
thank you !
| Is This Answer Correct ? | 25 Yes | 6 No |
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