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What will be the output-
for(i=1;i<=3;i++)
{
printf("%d",i);
continue;
i++;
}
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Answer Posted / chetan
This will not result in a Compiler-error, because "Unreachable-code" is a warning in C, not a compilation error.
The output will be:
123
| Is This Answer Correct ? | 6 Yes | 2 No |
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