main()
{
int *j;
{
int i=10;
j=&i;
}
printf("%d",*j);
}
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Answer Posted / jerome.s,final year eee,adhipa
There i-is initialised by 10.
and j-also initialised by address of i.
so *j is the value in the address of j.
therefore,
*j=i=10.
OUTPUT:
10
| Is This Answer Correct ? | 7 Yes | 1 No |
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