Answer Posted / kiranreddy munnangi
As you all know ,we measure pH of all of samples in
water.And the reaction of water is
H<+ + OH<- ------> H20
In this equilibration constant kw is
[H+] [OH-] = Kw = 1 X 10-14
By applying -log on both sides
-log [OH-] - log [H+] = 14
You know pH= - log [H+]
Therefore, pH = 14 - (-log [OH-])
You can see from this equation that the higher than
concentration of OH- ions, the lower the value of -log [OH-
]. If the concentration of OH- ions reaches 1 mol/dm3 , the
value of -log [OH-] is zero, which, according to the
equation, gives pH=14.0.
However, if the concentration of OH- ions exceeds 1 mol/dm3
(which is very rare), the value of -log [OH-] would be
negative, which, according to the equation, gives a pH of
greater than 14.0.
Therefore, the pH range does not necessarily have a maximum
of 14.0, since there is no limit to the concentration of a
base.
Is This Answer Correct ? | 33 Yes | 2 No |
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