Answer Posted / p govind rao
if an object of a derived class is assigned to a base class
object,the compiler accepts it.but it copies only the base
portion of the object
#include<iostream>
using namespace std;
class base
{
public:
int i,j;
base(){i=2;j=3;}
virtual void show(){cout<<"i = "<<i<<endl<<"j = "<<j<<endl;}
};
class derived :public base
{
public :
int k;
derived(){k=4;}
void show() {
base::show();
cout<<"k = "<<k<<endl;
}
};
int main()
{
base b;
derived d;
d.show();
b=d;
b.show();
return 0;
}
OutPut is
i = 2
j = 3
k = 4
---------------
i = 2
j = 3
here b contains i and j where as d contains i,j&k.On
assignment only i and j of the d get copied into i and j of
b. k doesnot be copied. on the effect object d got sliced.
| Is This Answer Correct ? | 12 Yes | 1 No |
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