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Answer Posted / sibnath halder
Assuming that you want to use 8 bits of whatever bytes you
have, you could use
char swapbyte(unsigned char c)
{ unsigned char result=0;
for(int i=0;i<8;++i)
{ result=result<<1;
result|=(c&1);
c=c>>1;
}
return result;
}
| Is This Answer Correct ? | 0 Yes | 1 No |
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