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sql query to get zero records from a table having n no of
records

Answer Posted / xyz

select * from emp minus
select * from emp;

Is This Answer Correct ?    12 Yes 4 No



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create or replace procedure search_matter(empno varchar2) as sql_stmt varchar2(200); stmt varchar2(200); v_table_name varchar2(200); val_pres number; inp_value varchar2(200); type obj_typ is table of cols.column_name%type index by binary_integer; type all_col is table of varchar2(100) index by binary_integer; typ_obj_typ obj_typ; typ_all_col all_col; begin select object_name bulk collect into typ_obj_typ from user_tables,user_objects where table_name = object_name AND object_type = 'TABLE'; select empno into inp_value from dual; dbms_output.put_line('inp value : '||inp_value); for i in typ_obj_typ.first..typ_obj_typ.last loop v_table_name := NULL; v_table_name := typ_obj_typ(i); dbms_output.put_line(i||':'||typ_obj_typ(i)); dbms_output.put_line('....................'); sql_stmt := 'select column_name from cols where table_name = :1 and data_type in (''CHAR'', ''VARCHAR2'', ''NCHAR'', ''NVARCHAR2'',''NUMBER'')'; EXECUTE IMMEDIATE sql_stmt bulk collect into typ_all_col using typ_obj_typ(i); for inside in typ_all_col.first..typ_all_col.last loop dbms_output.put_line('sql stmt: '||sql_stmt); dbms_output.put_line('column name: '||typ_all_col(inside)||'table name: '||typ_obj_typ(i)); stmt := 'select count(*) from ||typ_obj_typ(i)||'; EXECUTE_IMMEDIATE stmt into val_pres ; if val_pres = 1 then dbms_output.put_line('value present col name: '||typ_all_col(inside)||'table name :'||typ_obj_typ(i)); end if; end loop; dbms_output.put_line('....................'); end loop; exception when others then dbms_output.put_line('sql code '||sqlcode||'Table name: '||v_table_name); dbms_output.put_line('sql message '||sqlerrm); end; Compile-time I am getting below error, Plz help to resolve. LINE/COL ERROR -------- ----------------------------------------------------------------- 47/23 PLS-00103: Encountered the symbol "STMT" when expecting one of the following: := . ( @ % ;

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