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Wrie a function which returns the most frequent number in a
list of integers. Handle the case of more than one number
which meets this criterion.
public static int[] GetFrequency(int[] list)

Answer Posted / paras malik

//I strongly feel that this signature is of java instead of
c++ with wrong signature name because function name
according to java conventions should start with small letter.

import java.util.HashMap;
import java.util.Set;

class A{



public static void main(String [] a){


int array[]={1,1,2,1,2,3,4,5,2,3,1};

array = GetFrequency(array);


for(int i =0;i<array.length;i++){

System.out.println(array[i] + "\n");

}

}



public static int[] GetFrequency(int [] array){

HashMap<Integer ,Integer > map = new HashMap<Integer,Integer>();



for(int i =0;i<array.length;i++){


if(map.get(array[i])==null) map.put(array[i],1);
else{
int k = map.get(array[i]);
map.put(array[i],k+1);

}

}

int a[] = new int[map.size()];

Set<Integer> set= map.keySet();
int i =0;
for(int s : set)
a[i++]=map.get(s);
return a;




}

}

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