Wrie a function which returns the most frequent number in a
list of integers. Handle the case of more than one number
which meets this criterion.
public static int[] GetFrequency(int[] list)
Answer Posted / paras malik
//I strongly feel that this signature is of java instead of
c++ with wrong signature name because function name
according to java conventions should start with small letter.
import java.util.HashMap;
import java.util.Set;
class A{
public static void main(String [] a){
int array[]={1,1,2,1,2,3,4,5,2,3,1};
array = GetFrequency(array);
for(int i =0;i<array.length;i++){
System.out.println(array[i] + "\n");
}
}
public static int[] GetFrequency(int [] array){
HashMap<Integer ,Integer > map = new HashMap<Integer,Integer>();
for(int i =0;i<array.length;i++){
if(map.get(array[i])==null) map.put(array[i],1);
else{
int k = map.get(array[i]);
map.put(array[i],k+1);
}
}
int a[] = new int[map.size()];
Set<Integer> set= map.keySet();
int i =0;
for(int s : set)
a[i++]=map.get(s);
return a;
}
}
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